(2x^2+4)=(x^2+29)

Solution for (2x^2+4)=(x^2+29) equation:

Simplifying
(2x2 + 4) = (x2 + 29)

Reorder the terms:
(4 + 2x2) = (x2 + 29)

Remove parenthesis around (4 + 2x2)
4 + 2x2 = (x2 + 29)

Reorder the terms:
4 + 2x2 = (29 + x2)

Remove parenthesis around (29 + x2)
4 + 2x2 = 29 + x2

Solving
4 + 2x2 = 29 + x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
4 + 2x2 + -1x2 = 29 + x2 + -1x2

Combine like terms: 2x2 + -1x2 = 1x2
4 + 1x2 = 29 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
4 + 1x2 = 29 + 0
4 + 1x2 = 29

Add '-4' to each side of the equation.
4 + -4 + 1x2 = 29 + -4

Combine like terms: 4 + -4 = 0
0 + 1x2 = 29 + -4
1x2 = 29 + -4

Combine like terms: 29 + -4 = 25
1x2 = 25

Divide each side by '1'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5}